Exploring Resistance: Achieving 3 Ω With Three 2 Ω Resistors
How Will You Connect Three Resistors Of Resistances 2 Ω, 3 Ω And 6 Ω To Obtain A Total Resistance Of
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How Can Three Resistors Of Resistances 2 Ω 3 Ω And 6Ω Be Connected To Give A Total Resistance Of A 4 Ω B 1 Ω?
To achieve the desired total resistances of either 4 Ω or 1 Ω, we have three resistors available with values of 2 Ω, 3 Ω, and 6 Ω. (a) To attain a total resistance of 4 Ω, we connect the 2 Ω resistor in series with the combination of the 3 Ω and 6 Ω resistors arranged in parallel. This configuration results in the desired total resistance of 4 Ω. (b) Alternatively, if we aim for a total resistance of 1 Ω, we connect all three resistors (2 Ω, 3 Ω, and 6 Ω) in parallel with each other. This arrangement yields a total resistance of 1 Ω. These setups demonstrate how the combination of resistors can be manipulated to achieve specific total resistance values.
What Is The Combined Resistance Of A 2 Ω And A 3 Ω Resistor Connected In Series?
To determine the combined resistance of two resistors connected in series, you can use the formula for calculating equivalent resistance, which is represented as R_eq = R_1 + R_2. In this case, we have a 2 Ω resistor (R_1) and a 3 Ω resistor (R_2) connected in series.
To find the total resistance (R_eq), simply add the individual resistances together:
R_eq = 2 Ω + 3 Ω = 5 Ω.
So, when a 2 Ω resistor and a 3 Ω resistor are connected in series, the combined resistance is 5 Ω. This means that if you were to replace these two resistors with a single resistor, it would need to have a resistance of 5 Ω to have the same effect in the circuit.
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